Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1010100110010010011110 |
3 | 1201102100020112021122220220 |
4 | 2332302000322212102132 |
5 | 3204300101134012342 |
6 | 43514500324422210 |
7 | 2522124003033036 |
oct | 276620072462236 |
9 | 51370215248826 |
10 | 13110403032222 |
11 | 41a50aa7a6991 |
12 | 1578a73547966 |
13 | 7413c8818b12 |
14 | 33479295c8c6 |
15 | 17b071d415ec |
hex | bec80ea649e |
13110403032222 has 16 divisors (see below), whose sum is σ = 27763206421392. Its totient is φ = 4113067617920.
The previous prime is 13110403032211. The next prime is 13110403032263. The reversal of 13110403032222 is 22223030401131.
13110403032222 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13110403032192 and 13110403032201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64266681429 + ... + 64266681632.
It is an arithmetic number, because the mean of its divisors is an integer number (1735200401337).
Almost surely, 213110403032222 is an apocalyptic number.
13110403032222 is an abundant number, since it is smaller than the sum of its proper divisors (14652803389170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110403032222 is a wasteful number, since it uses less digits than its factorization.
13110403032222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128533363083.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13110403032222 its reverse (22223030401131), we get a palindrome (35333433433353).
The spelling of 13110403032222 in words is "thirteen trillion, one hundred ten billion, four hundred three million, thirty-two thousand, two hundred twenty-two".
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