Base | Representation |
---|---|
bin | 1011111011001000001100… |
… | …1100111110011001110100 |
3 | 1201102100100012111011010121 |
4 | 2332302003030332121310 |
5 | 3204300140444412040 |
6 | 43514504215101324 |
7 | 2522124650140132 |
oct | 276620314763164 |
9 | 51370305434117 |
10 | 13110441404020 |
11 | 41a511a425214 |
12 | 1578a84371844 |
13 | 74140376251c |
14 | 334797aaa752 |
15 | 17b0753c0c4a |
hex | bec8333e674 |
13110441404020 has 48 divisors (see below), whose sum is σ = 28263971026368. Its totient is φ = 5105534112000.
The previous prime is 13110441403987. The next prime is 13110441404051. The reversal of 13110441404020 is 2040414401131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24564481 + ... + 25092520.
It is an arithmetic number, because the mean of its divisors is an integer number (588832729716).
Almost surely, 213110441404020 is an apocalyptic number.
13110441404020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13110441404020 is an abundant number, since it is smaller than the sum of its proper divisors (15153529622348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110441404020 is a wasteful number, since it uses less digits than its factorization.
13110441404020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49657360 (or 49657358 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13110441404020 its reverse (2040414401131), we get a palindrome (15150855805151).
The spelling of 13110441404020 in words is "thirteen trillion, one hundred ten billion, four hundred forty-one million, four hundred four thousand, twenty".
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