Base | Representation |
---|---|
bin | 1011111011001000010000… |
… | …1001011001100010000111 |
3 | 1201102100101022021220012111 |
4 | 2332302010021121202013 |
5 | 3204300204023300113 |
6 | 43514505542401451 |
7 | 2522125231601164 |
oct | 276620411314207 |
9 | 51370338256174 |
10 | 13110457243783 |
11 | 41a5128363929 |
12 | 1578a89730287 |
13 | 741406b1a173 |
14 | 334799c3106b |
15 | 17b07699e13d |
hex | bec84259887 |
13110457243783 has 2 divisors, whose sum is σ = 13110457243784. Its totient is φ = 13110457243782.
The previous prime is 13110457243781. The next prime is 13110457243823. The reversal of 13110457243783 is 38734275401131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13110457243783 - 21 = 13110457243781 is a prime.
Together with 13110457243781, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110457243781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555228621891 + 6555228621892.
It is an arithmetic number, because the mean of its divisors is an integer number (6555228621892).
Almost surely, 213110457243783 is an apocalyptic number.
13110457243783 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110457243783 is an equidigital number, since it uses as much as digits as its factorization.
13110457243783 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 13110457243783 in words is "thirteen trillion, one hundred ten billion, four hundred fifty-seven million, two hundred forty-three thousand, seven hundred eighty-three".
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