Base | Representation |
---|---|
bin | 111101000011010000… |
… | …0000001011011110011 |
3 | 110112101222020112020212 |
4 | 1322012200001123303 |
5 | 4122001010412212 |
6 | 140121251054335 |
7 | 12320626606151 |
oct | 1720640013363 |
9 | 415358215225 |
10 | 131105560307 |
11 | 50668741a37 |
12 | 214aaba13ab |
13 | c494c51327 |
14 | 64ba2543d1 |
15 | 3624e46e22 |
hex | 1e868016f3 |
131105560307 has 2 divisors, whose sum is σ = 131105560308. Its totient is φ = 131105560306.
The previous prime is 131105560279. The next prime is 131105560309. The reversal of 131105560307 is 703065501131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131105560307 - 220 = 131104511731 is a prime.
Together with 131105560309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131105560309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65552780153 + 65552780154.
It is an arithmetic number, because the mean of its divisors is an integer number (65552780154).
Almost surely, 2131105560307 is an apocalyptic number.
131105560307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131105560307 is an equidigital number, since it uses as much as digits as its factorization.
131105560307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 32.
The spelling of 131105560307 in words is "one hundred thirty-one billion, one hundred five million, five hundred sixty thousand, three hundred seven".
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