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131110101020 = 2256555505051
BaseRepresentation
bin111101000011011000…
…1010110000000011100
3110112102021210012221102
41322012301112000130
54122003141213040
6140121532252232
712321013320323
oct1720661260034
9415367705842
10131110101020
1150670263498
12214b0611078
13c495b81042
1464baab70ba
153625542515
hex1e86c5601c

131110101020 has 12 divisors (see below), whose sum is σ = 275331212184. Its totient is φ = 52444040400.

The previous prime is 131110100941. The next prime is 131110101037. The reversal of 131110101020 is 20101011131.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 131110100992 and 131110101010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3277752506 + ... + 3277752545.

It is an arithmetic number, because the mean of its divisors is an integer number (22944267682).

Almost surely, 2131110101020 is an apocalyptic number.

131110101020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131110101020 is an abundant number, since it is smaller than the sum of its proper divisors (144221111164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131110101020 is a wasteful number, since it uses less digits than its factorization.

131110101020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6555505060 (or 6555505058 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 131110101020 its reverse (20101011131), we get a palindrome (151211112151).

The spelling of 131110101020 in words is "one hundred thirty-one billion, one hundred ten million, one hundred one thousand, twenty".

Divisors: 1 2 4 5 10 20 6555505051 13111010102 26222020204 32777525255 65555050510 131110101020