Base | Representation |
---|---|
bin | 11000011010111101… |
… | …00101011101100111 |
3 | 1020211201201000000121 |
4 | 30031132211131213 |
5 | 203322410222323 |
6 | 10004554422411 |
7 | 642621601126 |
oct | 141536453547 |
9 | 36751630017 |
10 | 13111023463 |
11 | 5618915a8a |
12 | 265aa31a07 |
13 | 130c3a4b65 |
14 | 8c53c9abd |
15 | 51b082a5d |
hex | 30d7a5767 |
13111023463 has 2 divisors, whose sum is σ = 13111023464. Its totient is φ = 13111023462.
The previous prime is 13111023427. The next prime is 13111023479. The reversal of 13111023463 is 36432011131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111023463 - 229 = 12574152551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111023763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555511731 + 6555511732.
It is an arithmetic number, because the mean of its divisors is an integer number (6555511732).
Almost surely, 213111023463 is an apocalyptic number.
13111023463 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111023463 is an equidigital number, since it uses as much as digits as its factorization.
13111023463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13111023463 its reverse (36432011131), we get a palindrome (49543034594).
The spelling of 13111023463 in words is "thirteen billion, one hundred eleven million, twenty-three thousand, four hundred sixty-three".
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