Base | Representation |
---|---|
bin | 10011000101000011110… |
… | …011101101101001011011 |
3 | 11122100011222221202202002 |
4 | 103011003303231221123 |
5 | 132440114234430232 |
6 | 2442151240031215 |
7 | 163503226455212 |
oct | 23050363555133 |
9 | 4570158852662 |
10 | 1311102655067 |
11 | 4660432a5287 |
12 | 19212576250b |
13 | 96837384c1a |
14 | 47659d3c079 |
15 | 241889e0b62 |
hex | 13143ceda5b |
1311102655067 has 2 divisors, whose sum is σ = 1311102655068. Its totient is φ = 1311102655066.
The previous prime is 1311102655063. The next prime is 1311102655117. The reversal of 1311102655067 is 7605562011131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311102655067 - 22 = 1311102655063 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311102655067.
It is not a weakly prime, because it can be changed into another prime (1311102655063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551327533 + 655551327534.
It is an arithmetic number, because the mean of its divisors is an integer number (655551327534).
Almost surely, 21311102655067 is an apocalyptic number.
1311102655067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311102655067 is an equidigital number, since it uses as much as digits as its factorization.
1311102655067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 38.
Adding to 1311102655067 its reverse (7605562011131), we get a palindrome (8916664666198).
The spelling of 1311102655067 in words is "one trillion, three hundred eleven billion, one hundred two million, six hundred fifty-five thousand, sixty-seven".
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