Base | Representation |
---|---|
bin | 1011111011001010011001… |
… | …1010000000010001010111 |
3 | 1201102101212100211122211102 |
4 | 2332302212122000101113 |
5 | 3204302343144201403 |
6 | 43515042554100315 |
7 | 2522145411252551 |
oct | 276624632002127 |
9 | 51371770748742 |
10 | 13111032022103 |
11 | 41a53a2855334 |
12 | 157900a11a69b |
13 | 741498c24992 |
14 | 3348122d04d1 |
15 | 17b0ac188b88 |
hex | beca6680457 |
13111032022103 has 2 divisors, whose sum is σ = 13111032022104. Its totient is φ = 13111032022102.
The previous prime is 13111032022037. The next prime is 13111032022147. The reversal of 13111032022103 is 30122023011131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111032022103 - 28 = 13111032021847 is a prime.
It is a super-2 number, since 2×131110320221032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111032022003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555516011051 + 6555516011052.
It is an arithmetic number, because the mean of its divisors is an integer number (6555516011052).
Almost surely, 213111032022103 is an apocalyptic number.
13111032022103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111032022103 is an equidigital number, since it uses as much as digits as its factorization.
13111032022103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13111032022103 its reverse (30122023011131), we get a palindrome (43233055033234).
The spelling of 13111032022103 in words is "thirteen trillion, one hundred eleven billion, thirty-two million, twenty-two thousand, one hundred three".
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