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13111032022103 is a prime number
BaseRepresentation
bin1011111011001010011001…
…1010000000010001010111
31201102101212100211122211102
42332302212122000101113
53204302343144201403
643515042554100315
72522145411252551
oct276624632002127
951371770748742
1013111032022103
1141a53a2855334
12157900a11a69b
13741498c24992
143348122d04d1
1517b0ac188b88
hexbeca6680457

13111032022103 has 2 divisors, whose sum is σ = 13111032022104. Its totient is φ = 13111032022102.

The previous prime is 13111032022037. The next prime is 13111032022147. The reversal of 13111032022103 is 30122023011131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111032022103 - 28 = 13111032021847 is a prime.

It is a super-2 number, since 2×131110320221032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111032022003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555516011051 + 6555516011052.

It is an arithmetic number, because the mean of its divisors is an integer number (6555516011052).

Almost surely, 213111032022103 is an apocalyptic number.

13111032022103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111032022103 is an equidigital number, since it uses as much as digits as its factorization.

13111032022103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13111032022103 its reverse (30122023011131), we get a palindrome (43233055033234).

The spelling of 13111032022103 in words is "thirteen trillion, one hundred eleven billion, thirty-two million, twenty-two thousand, one hundred three".