13111111123081 has 2 divisors, whose sum is σ = 13111111123082. Its totient is φ = 13111111123080.

The previous prime is 13111111123057. The next prime is 13111111123151. The reversal of 13111111123081 is 18032111111131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8192097249856 + 4919013873225 = 2862184^2 + 2217885^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111111123081 - 2¹⁵ = 13111111090313 is a prime.

It is a super-2 number, since 2×13111111123081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13111111124081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555555561540 + 6555555561541.

It is an arithmetic number, because the mean of its divisors is an integer number (6555555561541).

Almost surely, 2^{13111111123081} is an apocalyptic number.

It is an amenable number.

13111111123081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111111123081 is an equidigital number, since it uses as much as digits as its factorization.

13111111123081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 25.

The spelling of 13111111123081 in words is "thirteen trillion, one hundred eleven billion, one hundred eleven million, one hundred twenty-three thousand, eighty-one".