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13111111123151 is a prime number
BaseRepresentation
bin1011111011001010101100…
…0111110000000011001111
31201102102001212200102001212
42332302223013300003033
53204303023421420101
643515054501325035
72522150361513056
oct276625307600317
951372055612055
1013111111123151
1141a54334720a8
12157903070677b
137414ac42bb32
1433481ca0139d
1517b0b40b11bb
hexbecab1f00cf

13111111123151 has 2 divisors, whose sum is σ = 13111111123152. Its totient is φ = 13111111123150.

The previous prime is 13111111123081. The next prime is 13111111123163. The reversal of 13111111123151 is 15132111111131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111111123151 - 218 = 13111110861007 is a prime.

It is a super-2 number, since 2×131111111231512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111111623151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555555561575 + 6555555561576.

It is an arithmetic number, because the mean of its divisors is an integer number (6555555561576).

Almost surely, 213111111123151 is an apocalyptic number.

13111111123151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111111123151 is an equidigital number, since it uses as much as digits as its factorization.

13111111123151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90, while the sum is 23.

Adding to 13111111123151 its reverse (15132111111131), we get a palindrome (28243222234282).

The spelling of 13111111123151 in words is "thirteen trillion, one hundred eleven billion, one hundred eleven million, one hundred twenty-three thousand, one hundred fifty-one".