13111111311320 has 32 divisors (see below), whose sum is σ = 32181818674320. Its totient is φ = 4767676840320.

The previous prime is 13111111311299. The next prime is 13111111311343. The reversal of 13111111311320 is 2311311111131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13111111311292 and 13111111311301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14898989687 + ... + 14898990566.

Almost surely, 2^{13111111311320} is an apocalyptic number.

13111111311320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13111111311320 is an abundant number, since it is smaller than the sum of its proper divisors (19070707363000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111111311320 is a wasteful number, since it uses less digits than its factorization.

13111111311320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29797980275 (or 29797980271 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 13111111311320 its reverse (2311311111131), we get a palindrome (15422422422451).

It can be divided in two parts, 13111111 and 311320, that added together give a palindrome (13422431).

The spelling of 13111111311320 in words is "thirteen trillion, one hundred eleven billion, one hundred eleven million, three hundred eleven thousand, three hundred twenty".