Base | Representation |
---|---|
bin | 11000011010111101… |
… | …11011000101010100 |
3 | 1020211201212111111111 |
4 | 30031132323011110 |
5 | 203322421041040 |
6 | 10005000344404 |
7 | 642622420246 |
oct | 141536730524 |
9 | 36751774444 |
10 | 13111112020 |
11 | 5618976576 |
12 | 265aa75104 |
13 | 130c406266 |
14 | 8c5410096 |
15 | 51b09ddea |
hex | 30d7bb154 |
13111112020 has 48 divisors (see below), whose sum is σ = 28454681808. Its totient is φ = 5071216640.
The previous prime is 13111112017. The next prime is 13111112041. The reversal of 13111112020 is 2021111131.
It is a happy number.
It can be written as a sum of positive squares in 8 ways, for example, as 1263660304 + 11847451716 = 35548^2 + 108846^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21912 + ... + 163408.
It is an arithmetic number, because the mean of its divisors is an integer number (592805871).
Almost surely, 213111112020 is an apocalyptic number.
13111112020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13111112020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14227340904).
13111112020 is an abundant number, since it is smaller than the sum of its proper divisors (15343569788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111112020 is a wasteful number, since it uses less digits than its factorization.
13111112020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141660 (or 141658 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 13111112020 its reverse (2021111131), we get a palindrome (15132223151).
It can be divided in two parts, 1311111 and 2020, that added together give a palindrome (1313131).
The spelling of 13111112020 in words is "thirteen billion, one hundred eleven million, one hundred twelve thousand, twenty".
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