Base | Representation |
---|---|
bin | 1011111011001010101100… |
… | …1101000011001110010000 |
3 | 1201102102001222021222202112 |
4 | 2332302223031003032100 |
5 | 3204303024300344100 |
6 | 43515054551204452 |
7 | 2522150406360260 |
oct | 276625315031620 |
9 | 51372058258675 |
10 | 13111112512400 |
11 | 41a5434230941 |
12 | 1579031076728 |
13 | 7414ac7c7286 |
14 | 33481cc837a0 |
15 | 17b0b4287b35 |
hex | becab343390 |
13111112512400 has 60 divisors (see below), whose sum is σ = 35999368934592. Its totient is φ = 4495238574720.
The previous prime is 13111112512387. The next prime is 13111112512417. The reversal of 13111112512400 is 421521111131.
13111112512400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2341267292 + ... + 2341272891.
Almost surely, 213111112512400 is an apocalyptic number.
13111112512400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111112512400 is an abundant number, since it is smaller than the sum of its proper divisors (22888256422192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111112512400 is a wasteful number, since it uses less digits than its factorization.
13111112512400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4682540208 (or 4682540197 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 13111112512400 its reverse (421521111131), we get a palindrome (13532633623531).
The spelling of 13111112512400 in words is "thirteen trillion, one hundred eleven billion, one hundred twelve million, five hundred twelve thousand, four hundred".
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