Base | Representation |
---|---|
bin | 11101110011111010110100… |
… | …101001000001111001000110 |
3 | 122012020002221010020111101021 |
4 | 131303322310221001321012 |
5 | 114141111220244112410 |
6 | 1142503353240221354 |
7 | 36421320550531651 |
oct | 3563726451017106 |
9 | 565202833214337 |
10 | 131111202332230 |
11 | 38859a4872222a |
12 | 1285629046a85a |
13 | 582096c17a7c3 |
14 | 2453b5d364898 |
15 | 1025783753eda |
hex | 773eb4a41e46 |
131111202332230 has 8 divisors (see below), whose sum is σ = 236000164198032. Its totient is φ = 52444480932888.
The previous prime is 131111202332177. The next prime is 131111202332249. The reversal of 131111202332230 is 32233202111131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 131111202332195 and 131111202332204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6555560116602 + ... + 6555560116621.
It is an arithmetic number, because the mean of its divisors is an integer number (29500020524754).
Almost surely, 2131111202332230 is an apocalyptic number.
131111202332230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131111202332230 is a deficient number, since it is larger than the sum of its proper divisors (104888961865802).
131111202332230 is a wasteful number, since it uses less digits than its factorization.
131111202332230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13111120233230.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131111202332230 its reverse (32233202111131), we get a palindrome (163344404443361).
The spelling of 131111202332230 in words is "one hundred thirty-one trillion, one hundred eleven billion, two hundred two million, three hundred thirty-two thousand, two hundred thirty".
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