13111122033341 has 2 divisors, whose sum is σ = 13111122033342. Its totient is φ = 13111122033340.

The previous prime is 13111122033323. The next prime is 13111122033343. The reversal of 13111122033341 is 14333022111131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12741658646116 + 369463387225 = 3569546^2 + 607835^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111122033341 - 2¹⁸ = 13111121771197 is a prime.

It is a super-3 number, since 3×13111122033341³ (a number of 40 digits) contains 333 as substring.

Together with 13111122033343, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13111122033341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111122033343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555561016670 + 6555561016671.

It is an arithmetic number, because the mean of its divisors is an integer number (6555561016671).

Almost surely, 2^{13111122033341} is an apocalyptic number.

It is an amenable number.

13111122033341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111122033341 is an equidigital number, since it uses as much as digits as its factorization.

13111122033341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 13111122033341 its reverse (14333022111131), we get a palindrome (27444144144472).

The spelling of 13111122033341 in words is "thirteen trillion, one hundred eleven billion, one hundred twenty-two million, thirty-three thousand, three hundred forty-one".