Base | Representation |
---|---|
bin | 10011000101000100011… |
… | …100110100010000010010 |
3 | 11122100012202020012012221 |
4 | 103011010130310100102 |
5 | 132440130014230114 |
6 | 2442152303011254 |
7 | 163503420163132 |
oct | 23050434642022 |
9 | 4570182205187 |
10 | 1311113430034 |
11 | 466049394711 |
12 | 192129299b2a |
13 | 96839688445 |
14 | 4765b544ac2 |
15 | 2418991d524 |
hex | 13144734412 |
1311113430034 has 32 divisors (see below), whose sum is σ = 2075000716800. Its totient is φ = 620490904320.
The previous prime is 1311113429993. The next prime is 1311113430073. The reversal of 1311113430034 is 4300343111131.
It is a super-2 number, since 2×13111134300342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311113429990 and 1311113430008.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 189079 + ... + 1630330.
It is an arithmetic number, because the mean of its divisors is an integer number (64843772400).
Almost surely, 21311113430034 is an apocalyptic number.
1311113430034 is a deficient number, since it is larger than the sum of its proper divisors (763887286766).
1311113430034 is a wasteful number, since it uses less digits than its factorization.
1311113430034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1819698.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1311113430034 its reverse (4300343111131), we get a palindrome (5611456541165).
The spelling of 1311113430034 in words is "one trillion, three hundred eleven billion, one hundred thirteen million, four hundred thirty thousand, thirty-four".
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