Base | Representation |
---|---|
bin | 11000011010111110… |
… | …00010111001010011 |
3 | 1020211201221010101122 |
4 | 30031133002321103 |
5 | 203322423102034 |
6 | 10005001152455 |
7 | 642622612451 |
oct | 141537027123 |
9 | 36751833348 |
10 | 13111144019 |
11 | 5618998616 |
12 | 265aa8b72b |
13 | 130c4179ac |
14 | 8c541b9d1 |
15 | 51b0a862e |
hex | 30d7c2e53 |
13111144019 has 2 divisors, whose sum is σ = 13111144020. Its totient is φ = 13111144018.
The previous prime is 13111143989. The next prime is 13111144021. The reversal of 13111144019 is 91044111131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111144019 - 220 = 13110095443 is a prime.
It is a super-2 number, since 2×131111440192 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 13111144021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13111149019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555572009 + 6555572010.
It is an arithmetic number, because the mean of its divisors is an integer number (6555572010).
Almost surely, 213111144019 is an apocalyptic number.
13111144019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111144019 is an equidigital number, since it uses as much as digits as its factorization.
13111144019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 26.
The spelling of 13111144019 in words is "thirteen billion, one hundred eleven million, one hundred forty-four thousand, nineteen".
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