Base | Representation |
---|---|
bin | 11000011010111110… |
… | …00010111001010101 |
3 | 1020211201221010101201 |
4 | 30031133002321111 |
5 | 203322423102041 |
6 | 10005001152501 |
7 | 642622612453 |
oct | 141537027125 |
9 | 36751833351 |
10 | 13111144021 |
11 | 5618998618 |
12 | 265aa8b731 |
13 | 130c4179b1 |
14 | 8c541b9d3 |
15 | 51b0a8631 |
hex | 30d7c2e55 |
13111144021 has 2 divisors, whose sum is σ = 13111144022. Its totient is φ = 13111144020.
The previous prime is 13111144019. The next prime is 13111144027. The reversal of 13111144021 is 12044111131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9769147921 + 3341996100 = 98839^2 + 57810^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111144021 - 21 = 13111144019 is a prime.
Together with 13111144019, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13111144021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111144027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555572010 + 6555572011.
It is an arithmetic number, because the mean of its divisors is an integer number (6555572011).
Almost surely, 213111144021 is an apocalyptic number.
It is an amenable number.
13111144021 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111144021 is an equidigital number, since it uses as much as digits as its factorization.
13111144021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 13111144021 its reverse (12044111131), we get a palindrome (25155255152).
The spelling of 13111144021 in words is "thirteen billion, one hundred eleven million, one hundred forty-four thousand, twenty-one".
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