Base | Representation |
---|---|
bin | 10011000101000100111… |
… | …110010001110110101111 |
3 | 11122100020100201212010201 |
4 | 103011010332101312233 |
5 | 132440134240431111 |
6 | 2442153215014331 |
7 | 163503554556355 |
oct | 23050476216657 |
9 | 4570210655121 |
10 | 1311122202031 |
11 | 4660533361a4 |
12 | 19213020a3a7 |
13 | 9683b43a085 |
14 | 4765c7897d5 |
15 | 2418a5a26c1 |
hex | 13144f91daf |
1311122202031 has 2 divisors, whose sum is σ = 1311122202032. Its totient is φ = 1311122202030.
The previous prime is 1311122202029. The next prime is 1311122202079. The reversal of 1311122202031 is 1302022211131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311122202031 - 21 = 1311122202029 is a prime.
It is a super-2 number, since 2×13111222020312 (a number of 25 digits) contains 22 as substring.
Together with 1311122202029, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311122208031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655561101015 + 655561101016.
It is an arithmetic number, because the mean of its divisors is an integer number (655561101016).
Almost surely, 21311122202031 is an apocalyptic number.
1311122202031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311122202031 is an equidigital number, since it uses as much as digits as its factorization.
1311122202031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1311122202031 its reverse (1302022211131), we get a palindrome (2613144413162).
The spelling of 1311122202031 in words is "one trillion, three hundred eleven billion, one hundred twenty-two million, two hundred two thousand, thirty-one".
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