Base | Representation |
---|---|
bin | 10011000101000100111… |
… | …111000100101001011111 |
3 | 11122100020101010102112012 |
4 | 103011010333010221133 |
5 | 132440134314110304 |
6 | 2442153223301435 |
7 | 163503556414046 |
oct | 23050477045137 |
9 | 4570211112465 |
10 | 1311122410079 |
11 | 466053468539 |
12 | 1921302aa87b |
13 | 9683b4b0991 |
14 | 4765c80155d |
15 | 2418a5e416e |
hex | 13144fc4a5f |
1311122410079 has 2 divisors, whose sum is σ = 1311122410080. Its totient is φ = 1311122410078.
The previous prime is 1311122410043. The next prime is 1311122410133. The reversal of 1311122410079 is 9700142211131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9700142211131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311122410079 - 28 = 1311122409823 is a prime.
It is a super-2 number, since 2×13111224100792 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311122460079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655561205039 + 655561205040.
It is an arithmetic number, because the mean of its divisors is an integer number (655561205040).
Almost surely, 21311122410079 is an apocalyptic number.
1311122410079 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311122410079 is an equidigital number, since it uses as much as digits as its factorization.
1311122410079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 32.
The spelling of 1311122410079 in words is "one trillion, three hundred eleven billion, one hundred twenty-two million, four hundred ten thousand, seventy-nine".
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