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1311123331321 is a prime number
BaseRepresentation
bin10011000101000101000…
…010100101100011111001
311122100020102212020020021
4103011011002211203321
5132440140033100241
62442153255130441
7163503600301636
oct23050502454371
94570212766207
101311123331321
11466053a376a1
12192130673a21
139683b7440ab
144765c9a118d
152418a7270d1
hex131450a58f9

1311123331321 has 2 divisors, whose sum is σ = 1311123331322. Its totient is φ = 1311123331320.

The previous prime is 1311123331211. The next prime is 1311123331333. The reversal of 1311123331321 is 1231333211131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1038676914025 + 272446417296 = 1019155^2 + 521964^2 .

It is an emirp because it is prime and its reverse (1231333211131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311123331321 - 215 = 1311123298553 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311123331351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655561665660 + 655561665661.

It is an arithmetic number, because the mean of its divisors is an integer number (655561665661).

Almost surely, 21311123331321 is an apocalyptic number.

It is an amenable number.

1311123331321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311123331321 is an equidigital number, since it uses as much as digits as its factorization.

1311123331321 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 25.

Adding to 1311123331321 its reverse (1231333211131), we get a palindrome (2542456542452).

The spelling of 1311123331321 in words is "one trillion, three hundred eleven billion, one hundred twenty-three million, three hundred thirty-one thousand, three hundred twenty-one".