13111302122320 has 40 divisors (see below), whose sum is σ = 30486060445824. Its totient is φ = 5244128072832.

The previous prime is 13111302122297. The next prime is 13111302122329. The reversal of 13111302122320 is 2322120311131.

13111302122320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 13111302122291 and 13111302122300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111302122329) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5061084 + ... + 7199803.

Almost surely, 2^{13111302122320} is an apocalyptic number.

13111302122320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13111302122320 is an abundant number, since it is smaller than the sum of its proper divisors (17374758323504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111302122320 is a wasteful number, since it uses less digits than its factorization.

13111302122320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12274267 (or 12274261 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13111302122320 its reverse (2322120311131), we get a palindrome (15433422433451).

The spelling of 13111302122320 in words is "thirteen trillion, one hundred eleven billion, three hundred two million, one hundred twenty-two thousand, three hundred twenty".