Base | Representation |
---|---|
bin | 10011000101000101100… |
… | …000000000110001111111 |
3 | 11122100020222101010101202 |
4 | 103011011200000301333 |
5 | 132440144021414431 |
6 | 2442154132330115 |
7 | 163504022666525 |
oct | 23050540006177 |
9 | 4570228333352 |
10 | 1311131044991 |
11 | 466058326029 |
12 | 19213317393b |
13 | 968402150b1 |
14 | 4765da0c315 |
15 | 2418b24c8cb |
hex | 13145800c7f |
1311131044991 has 2 divisors, whose sum is σ = 1311131044992. Its totient is φ = 1311131044990.
The previous prime is 1311131044987. The next prime is 1311131045089. The reversal of 1311131044991 is 1994401311131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1994401311131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311131044991 - 22 = 1311131044987 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311131044931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565522495 + 655565522496.
It is an arithmetic number, because the mean of its divisors is an integer number (655565522496).
Almost surely, 21311131044991 is an apocalyptic number.
1311131044991 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311131044991 is an equidigital number, since it uses as much as digits as its factorization.
1311131044991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 38.
The spelling of 1311131044991 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, forty-four thousand, nine hundred ninety-one".
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