13111310450142 has 32 divisors (see below), whose sum is σ = 29167208624160. Its totient is φ = 4365792339840.

The previous prime is 13111310450107. The next prime is 13111310450153. The reversal of 13111310450142 is 24105401311131.

13111310450142 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 13 + 104 + 501 + 42 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128961963 + ... + 129063590.

It is an arithmetic number, because the mean of its divisors is an integer number (911475269505).

Almost surely, 2^{13111310450142} is an apocalyptic number.

13111310450142 is an abundant number, since it is smaller than the sum of its proper divisors (16055898174018).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111310450142 is a wasteful number, since it uses less digits than its factorization.

13111310450142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258026505 (or 258026499 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 13111310450142 its reverse (24105401311131), we get a palindrome (37216711761273).

The spelling of 13111310450142 in words is "thirteen trillion, one hundred eleven billion, three hundred ten million, four hundred fifty thousand, one hundred forty-two".