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13111323033317 is a prime number
BaseRepresentation
bin1011111011001011011111…
…0000000111111011100101
31201102102121122102120011112
42332302313300013323211
53204303442144031232
643515131511314405
72522155543644005
oct276626760077345
951372548376145
1013111323033317
1141a553204a373
12157908b67ba05
137415142c6272
1433483cc04005
1517b0c79be4b2
hexbecb7c07ee5

13111323033317 has 2 divisors, whose sum is σ = 13111323033318. Its totient is φ = 13111323033316.

The previous prime is 13111323033299. The next prime is 13111323033337. The reversal of 13111323033317 is 71333032311131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11266857544996 + 1844465488321 = 3356614^2 + 1358111^2 .

It is an emirp because it is prime and its reverse (71333032311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111323033317 - 210 = 13111323032293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111323033337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555661516658 + 6555661516659.

It is an arithmetic number, because the mean of its divisors is an integer number (6555661516659).

Almost surely, 213111323033317 is an apocalyptic number.

It is an amenable number.

13111323033317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111323033317 is an equidigital number, since it uses as much as digits as its factorization.

13111323033317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10206, while the sum is 32.

Adding to 13111323033317 its reverse (71333032311131), we get a palindrome (84444355344448).

The spelling of 13111323033317 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-three million, thirty-three thousand, three hundred seventeen".