Base | Representation |
---|---|
bin | 1011111011001011100001… |
… | …0110001110110110001111 |
3 | 1201102102122100020002121012 |
4 | 2332302320112032312033 |
5 | 3204304002223214434 |
6 | 43515132505355435 |
7 | 2522156024601542 |
oct | 276627026166617 |
9 | 51372570202535 |
10 | 13111333023119 |
11 | 41a5537752901 |
12 | 1579092a98b7b |
13 | 7415163b32a6 |
14 | 334840284859 |
15 | 17b0c87e43ce |
hex | becb858ed8f |
13111333023119 has 2 divisors, whose sum is σ = 13111333023120. Its totient is φ = 13111333023118.
The previous prime is 13111333023083. The next prime is 13111333023127. The reversal of 13111333023119 is 91132033311131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111333023119 - 212 = 13111333019023 is a prime.
It is a super-2 number, since 2×131113330231192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111333023319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555666511559 + 6555666511560.
It is an arithmetic number, because the mean of its divisors is an integer number (6555666511560).
Almost surely, 213111333023119 is an apocalyptic number.
13111333023119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111333023119 is an equidigital number, since it uses as much as digits as its factorization.
13111333023119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 13111333023119 in words is "thirteen trillion, one hundred eleven billion, three hundred thirty-three million, twenty-three thousand, one hundred nineteen".
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