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1311134003440 = 2452922272932
BaseRepresentation
bin10011000101000101101…
…011010011000011110000
311122100021011221102121221
4103011011223103003300
5132440200301102230
62442154315554424
7163504060100662
oct23050553230360
94570234842557
101311134003440
11466059a66828
1219213415ba14
1396840a0c861
144766017c532
152418b63427a
hex13145ad30f0

1311134003440 has 180 divisors, whose sum is σ = 3181895691624. Its totient is φ = 502417685504.

The previous prime is 1311134003437. The next prime is 1311134003503. The reversal of 1311134003440 is 443004311131.

It is a happy number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 4474859934 + ... + 4474860226.

Almost surely, 21311134003440 is an apocalyptic number.

1311134003440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311134003440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1590947845812).

1311134003440 is an abundant number, since it is smaller than the sum of its proper divisors (1870761688184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311134003440 is an equidigital number, since it uses as much as digits as its factorization.

1311134003440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 884 (or 556 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1311134003440 its reverse (443004311131), we get a palindrome (1754138314571).

The spelling of 1311134003440 in words is "one trillion, three hundred eleven billion, one hundred thirty-four million, three thousand, four hundred forty".