Base | Representation |
---|---|
bin | 111101000011100000… |
… | …0101101111100010001 |
3 | 110112102120100222022222 |
4 | 1322013000231330101 |
5 | 4122010204144332 |
6 | 140122154510425 |
7 | 12321062504216 |
oct | 1720700557421 |
9 | 415376328288 |
10 | 131114131217 |
11 | 50672566433 |
12 | 214b1a35415 |
13 | c496962584 |
14 | 64bb445b0d |
15 | 3625a8b712 |
hex | 1e8702df11 |
131114131217 has 2 divisors, whose sum is σ = 131114131218. Its totient is φ = 131114131216.
The previous prime is 131114131189. The next prime is 131114131271. The reversal of 131114131217 is 712131411131.
It is a happy number.
Together with next prime (131114131271) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115796603521 + 15317527696 = 340289^2 + 123764^2 .
It is a cyclic number.
It is not a de Polignac number, because 131114131217 - 26 = 131114131153 is a prime.
It is not a weakly prime, because it can be changed into another prime (131114131277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557065608 + 65557065609.
It is an arithmetic number, because the mean of its divisors is an integer number (65557065609).
Almost surely, 2131114131217 is an apocalyptic number.
It is an amenable number.
131114131217 is a deficient number, since it is larger than the sum of its proper divisors (1).
131114131217 is an equidigital number, since it uses as much as digits as its factorization.
131114131217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 26.
Adding to 131114131217 its reverse (712131411131), we get a palindrome (843245542348).
The spelling of 131114131217 in words is "one hundred thirty-one billion, one hundred fourteen million, one hundred thirty-one thousand, two hundred seventeen".
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