Base | Representation |
---|---|
bin | 111101000011100000… |
… | …0101101111101000111 |
3 | 110112102120100222101222 |
4 | 1322013000231331013 |
5 | 4122010204200041 |
6 | 140122154510555 |
7 | 12321062504324 |
oct | 1720700557507 |
9 | 415376328358 |
10 | 131114131271 |
11 | 50672566482 |
12 | 214b1a3545b |
13 | c4969625c6 |
14 | 64bb445b4b |
15 | 3625a8b74b |
hex | 1e8702df47 |
131114131271 has 2 divisors, whose sum is σ = 131114131272. Its totient is φ = 131114131270.
The previous prime is 131114131217. The next prime is 131114131273. The reversal of 131114131271 is 172131411131.
It is a happy number.
Together with previous prime (131114131217) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131114131271 - 222 = 131109936967 is a prime.
Together with 131114131273, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131114131271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131114131273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557065635 + 65557065636.
It is an arithmetic number, because the mean of its divisors is an integer number (65557065636).
Almost surely, 2131114131271 is an apocalyptic number.
131114131271 is a deficient number, since it is larger than the sum of its proper divisors (1).
131114131271 is an equidigital number, since it uses as much as digits as its factorization.
131114131271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504, while the sum is 26.
The spelling of 131114131271 in words is "one hundred thirty-one billion, one hundred fourteen million, one hundred thirty-one thousand, two hundred seventy-one".
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