Base | Representation |
---|---|
bin | 111101000011100000… |
… | …0111100001101011111 |
3 | 110112102120110221111122 |
4 | 1322013000330031133 |
5 | 4122010213032123 |
6 | 140122200041155 |
7 | 12321063136502 |
oct | 1720700741537 |
9 | 415376427448 |
10 | 131114189663 |
11 | 506725a6336 |
12 | 214b1a631bb |
13 | c496983062 |
14 | 64bb45d139 |
15 | 3625a9dbc8 |
hex | 1e8703c35f |
131114189663 has 2 divisors, whose sum is σ = 131114189664. Its totient is φ = 131114189662.
The previous prime is 131114189641. The next prime is 131114189707. The reversal of 131114189663 is 366981411131.
It is an a-pointer prime, because the next prime (131114189707) can be obtained adding 131114189663 to its sum of digits (44).
It is a weak prime.
It is an emirp because it is prime and its reverse (366981411131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131114189663 - 226 = 131047080799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131114189363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557094831 + 65557094832.
It is an arithmetic number, because the mean of its divisors is an integer number (65557094832).
Almost surely, 2131114189663 is an apocalyptic number.
131114189663 is a deficient number, since it is larger than the sum of its proper divisors (1).
131114189663 is an equidigital number, since it uses as much as digits as its factorization.
131114189663 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 44.
The spelling of 131114189663 in words is "one hundred thirty-one billion, one hundred fourteen million, one hundred eighty-nine thousand, six hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •