131114241414040 has 128 divisors (see below), whose sum is σ = 313966769760000. Its totient is φ = 49107203719168.

The previous prime is 131114241414029. The next prime is 131114241414041. The reversal of 131114241414040 is 40414142411131.

It is a junction number, because it is equal to n+sod(n) for n = 131114241413993 and 131114241414011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131114241414041) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 170098944 + ... + 170868016.

It is an arithmetic number, because the mean of its divisors is an integer number (2452865388750).

Almost surely, 2^{131114241414040} is an apocalyptic number.

131114241414040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131114241414040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156983384880000).

131114241414040 is an abundant number, since it is smaller than the sum of its proper divisors (182852528345960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131114241414040 is a wasteful number, since it uses less digits than its factorization.

131114241414040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 770389 (or 770385 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 131114241414040 its reverse (40414142411131), we get a palindrome (171528383825171).

The spelling of 131114241414040 in words is "one hundred thirty-one trillion, one hundred fourteen billion, two hundred forty-one million, four hundred fourteen thousand, forty".