Base | Representation |
---|---|
bin | 10011000101000110010… |
… | …001100101101000111111 |
3 | 11122100021212211101121021 |
4 | 103011012101211220333 |
5 | 132440210333303043 |
6 | 2442155315045011 |
7 | 163504241315035 |
oct | 23050621455077 |
9 | 4570255741537 |
10 | 1311144041023 |
11 | 4660646a2153 |
12 | 1921375a0767 |
13 | 96842b1555b |
14 | 47661632555 |
15 | 2418c4683ed |
hex | 13146465a3f |
1311144041023 has 2 divisors, whose sum is σ = 1311144041024. Its totient is φ = 1311144041022.
The previous prime is 1311144040967. The next prime is 1311144041059. The reversal of 1311144041023 is 3201404411131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311144041023 - 217 = 1311143909951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311144041083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655572020511 + 655572020512.
It is an arithmetic number, because the mean of its divisors is an integer number (655572020512).
Almost surely, 21311144041023 is an apocalyptic number.
1311144041023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311144041023 is an equidigital number, since it uses as much as digits as its factorization.
1311144041023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1311144041023 its reverse (3201404411131), we get a palindrome (4512548452154).
The spelling of 1311144041023 in words is "one trillion, three hundred eleven billion, one hundred forty-four million, forty-one thousand, twenty-three".
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