Base | Representation |
---|---|
bin | 100111000100110… |
… | …1000110100011101 |
3 | 10101101011021202201 |
4 | 1032021220310131 |
5 | 10141123234331 |
6 | 334034251501 |
7 | 44330404555 |
oct | 11611506435 |
9 | 3341137681 |
10 | 1311149341 |
11 | 6131229a7 |
12 | 307126b91 |
13 | 17b83ca18 |
14 | c61c4165 |
15 | 7a193a61 |
hex | 4e268d1d |
1311149341 has 2 divisors, whose sum is σ = 1311149342. Its totient is φ = 1311149340.
The previous prime is 1311149297. The next prime is 1311149369. The reversal of 1311149341 is 1439411131.
It is an a-pointer prime, because the next prime (1311149369) can be obtained adding 1311149341 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1272348900 + 38800441 = 35670^2 + 6229^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311149341 - 211 = 1311147293 is a prime.
It is a super-2 number, since 2×13111493412 = 3438225188809468562, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311149381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655574670 + 655574671.
It is an arithmetic number, because the mean of its divisors is an integer number (655574671).
Almost surely, 21311149341 is an apocalyptic number.
It is an amenable number.
1311149341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311149341 is an equidigital number, since it uses as much as digits as its factorization.
1311149341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 28.
The square root of 1311149341 is about 36209.7962021329. The cubic root of 1311149341 is about 1094.5040854689.
The spelling of 1311149341 in words is "one billion, three hundred eleven million, one hundred forty-nine thousand, three hundred forty-one".
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