Base | Representation |
---|---|
bin | 11000011011000100… |
… | …10011110111000001 |
3 | 1020211210112121111022 |
4 | 30031202103313001 |
5 | 203323132444222 |
6 | 10005031355225 |
7 | 642633106031 |
oct | 141542236701 |
9 | 36753477438 |
10 | 13111999937 |
11 | 5619422693 |
12 | 265b222b15 |
13 | 130c65745a |
14 | 8c55a18c1 |
15 | 51b1c7042 |
hex | 30d893dc1 |
13111999937 has 2 divisors, whose sum is σ = 13111999938. Its totient is φ = 13111999936.
The previous prime is 13111999913. The next prime is 13111999961. The reversal of 13111999937 is 73999911131.
It is a balanced prime because it is at equal distance from previous prime (13111999913) and next prime (13111999961).
It can be written as a sum of positive squares in only one way, i.e., 12528101041 + 583898896 = 111929^2 + 24164^2 .
It is an emirp because it is prime and its reverse (73999911131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13111999937 - 214 = 13111983553 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111999907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555999968 + 6555999969.
It is an arithmetic number, because the mean of its divisors is an integer number (6555999969).
Almost surely, 213111999937 is an apocalyptic number.
It is an amenable number.
13111999937 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111999937 is an equidigital number, since it uses as much as digits as its factorization.
13111999937 is an evil number, because the sum of its binary digits is even.
The product of its digits is 413343, while the sum is 53.
The spelling of 13111999937 in words is "thirteen billion, one hundred eleven million, nine hundred ninety-nine thousand, nine hundred thirty-seven".
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