Base | Representation |
---|---|
bin | 11000011011000100… |
… | …10011110111011011 |
3 | 1020211210112121112021 |
4 | 30031202103313123 |
5 | 203323132444323 |
6 | 10005031355311 |
7 | 642633106066 |
oct | 141542236733 |
9 | 36753477467 |
10 | 13111999963 |
11 | 5619422707 |
12 | 265b222b37 |
13 | 130c65747a |
14 | 8c55a18dd |
15 | 51b1c705d |
hex | 30d893ddb |
13111999963 has 2 divisors, whose sum is σ = 13111999964. Its totient is φ = 13111999962.
The previous prime is 13111999961. The next prime is 13112000003. The reversal of 13111999963 is 36999911131.
It is a weak prime.
It is an emirp because it is prime and its reverse (36999911131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13111999963 - 21 = 13111999961 is a prime.
Together with 13111999961, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13111999963.
It is not a weakly prime, because it can be changed into another prime (13111999961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555999981 + 6555999982.
It is an arithmetic number, because the mean of its divisors is an integer number (6555999982).
Almost surely, 213111999963 is an apocalyptic number.
13111999963 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111999963 is an equidigital number, since it uses as much as digits as its factorization.
13111999963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 354294, while the sum is 52.
The spelling of 13111999963 in words is "thirteen billion, one hundred eleven million, nine hundred ninety-nine thousand, nine hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •