Base | Representation |
---|---|
bin | 11000011011000100… |
… | …10011110111011100 |
3 | 1020211210112121112022 |
4 | 30031202103313130 |
5 | 203323132444324 |
6 | 10005031355312 |
7 | 642633106100 |
oct | 141542236734 |
9 | 36753477468 |
10 | 13111999964 |
11 | 5619422708 |
12 | 265b222b38 |
13 | 130c65747b |
14 | 8c55a1900 |
15 | 51b1c705e |
hex | 30d893ddc |
13111999964 has 72 divisors (see below), whose sum is σ = 27166728960. Its totient is φ = 5520027744.
The previous prime is 13111999963. The next prime is 13112000003. The reversal of 13111999964 is 46999911131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111999961) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5501117 + ... + 5503499.
It is an arithmetic number, because the mean of its divisors is an integer number (377315680).
Almost surely, 213111999964 is an apocalyptic number.
13111999964 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13111999964, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13583364480).
13111999964 is an abundant number, since it is smaller than the sum of its proper divisors (14054728996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111999964 is a wasteful number, since it uses less digits than its factorization.
13111999964 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2887 (or 2878 counting only the distinct ones).
The product of its digits is 472392, while the sum is 53.
The spelling of 13111999964 in words is "thirteen billion, one hundred eleven million, nine hundred ninety-nine thousand, nine hundred sixty-four".
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