Base | Representation |
---|---|
bin | 1011111011001110001010… |
… | …0000101101101110110010 |
3 | 1201102111110122022021122021 |
4 | 2332303202200231232302 |
5 | 3204311424321223010 |
6 | 43515331015302054 |
7 | 2522212404405160 |
oct | 276634240555662 |
9 | 51374418267567 |
10 | 13112040414130 |
11 | 41a586aa90179 |
12 | 157924b97a92a |
13 | 7415c9b0c858 |
14 | 3348aa1c4230 |
15 | 17b11a9768da |
hex | bece282dbb2 |
13112040414130 has 32 divisors (see below), whose sum is σ = 26973479623680. Its totient is φ = 4495533489600.
The previous prime is 13112040414107. The next prime is 13112040414149. The reversal of 13112040414130 is 3141404021131.
It is a super-4 number, since 4×131120404141304 (a number of 54 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13112040414095 and 13112040414104.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18378516 + ... + 19078624.
It is an arithmetic number, because the mean of its divisors is an integer number (842921238240).
Almost surely, 213112040414130 is an apocalyptic number.
13112040414130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13112040414130 is an abundant number, since it is smaller than the sum of its proper divisors (13861439209550).
13112040414130 is a wasteful number, since it uses less digits than its factorization.
13112040414130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 967674.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13112040414130 its reverse (3141404021131), we get a palindrome (16253444435261).
The spelling of 13112040414130 in words is "thirteen trillion, one hundred twelve billion, forty million, four hundred fourteen thousand, one hundred thirty".
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