1311204911 has 2 divisors, whose sum is σ = 1311204912. Its totient is φ = 1311204910.

The previous prime is 1311204901. The next prime is 1311204913. The reversal of 1311204911 is 1194021131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311204911 is a prime.

Together with 1311204913, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311204913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655602455 + 655602456.

It is an arithmetic number, because the mean of its divisors is an integer number (655602456).

Almost surely, 2^1311204911 is an apocalyptic number.

1311204911 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311204911 is an equidigital number, since it uses as much as digits as its factorization.

1311204911 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 23.

The square root of 1311204911 is about 36210.5635277884. The cubic root of 1311204911 is about 1094.5195479162.

The spelling of 1311204911 in words is "one billion, three hundred eleven million, two hundred four thousand, nine hundred eleven".