131121003000020 has 48 divisors (see below), whose sum is σ = 301447733606208. Its totient is φ = 47511882850560.

The previous prime is 131121002999993. The next prime is 131121003000059. The reversal of 131121003000020 is 20000300121131.

It is a junction number, because it is equal to n+sod(n) for n = 131121002999959 and 131121003000004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1052949329 + ... + 1053073848.

It is an arithmetic number, because the mean of its divisors is an integer number (6280161116796).

Almost surely, 2^{131121003000020} is an apocalyptic number.

131121003000020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131121003000020 is an abundant number, since it is smaller than the sum of its proper divisors (170326730606188).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131121003000020 is a wasteful number, since it uses less digits than its factorization.

131121003000020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2106023480 (or 2106023478 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131121003000020 its reverse (20000300121131), we get a palindrome (151121303121151).

The spelling of 131121003000020 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three million, twenty", and thus it is an aban number.