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13112111 is a prime number
BaseRepresentation
bin110010000001…
…001100101111
3220200011102202
4302001030233
511324041421
61145012115
7216310505
oct62011457
926604382
1013112111
117446361
12448403b
13294125c
141a54675
15124010b
hexc8132f

13112111 has 2 divisors, whose sum is σ = 13112112. Its totient is φ = 13112110.

The previous prime is 13112081. The next prime is 13112129. The reversal of 13112111 is 11121131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112111 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13112092 and 13112101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556055 + 6556056.

It is an arithmetic number, because the mean of its divisors is an integer number (6556056).

Almost surely, 213112111 is an apocalyptic number.

13112111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112111 is an equidigital number, since it uses as much as digits as its factorization.

13112111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6, while the sum is 11.

The square root of 13112111 is about 3621.0648986175. The cubic root of 13112111 is about 235.8074593042.

Adding to 13112111 its reverse (11121131), we get a palindrome (24233242).

The spelling of 13112111 in words is "thirteen million, one hundred twelve thousand, one hundred eleven".