131121121023133 has 2 divisors, whose sum is σ = 131121121023134. Its totient is φ = 131121121023132.

The previous prime is 131121121023083. The next prime is 131121121023173. The reversal of 131121121023133 is 331320121121131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70032093516324 + 61089027506809 = 8368518^2 + 7815947^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131121121023133 is a prime.

It is a super-2 number, since 2×131121121023133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131121121023098 and 131121121023107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121121023173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560560511566 + 65560560511567.

It is an arithmetic number, because the mean of its divisors is an integer number (65560560511567).

Almost surely, 2^{131121121023133} is an apocalyptic number.

It is an amenable number.

131121121023133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121121023133 is an equidigital number, since it uses as much as digits as its factorization.

131121121023133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131121121023133 its reverse (331320121121131), we get a palindrome (462441242144264).

The spelling of 131121121023133 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred twenty-one million, twenty-three thousand, one hundred thirty-three".