Base | Representation |
---|---|
bin | 11000011011000101… |
… | …01111001111100111 |
3 | 1020211210202022100121 |
4 | 30031202233033213 |
5 | 203323200041403 |
6 | 10005034022411 |
7 | 642634054036 |
oct | 141542571747 |
9 | 36753668317 |
10 | 13112112103 |
11 | 5619499992 |
12 | 265b277a07 |
13 | 130c69651c |
14 | 8c55d071d |
15 | 51b1ea3bd |
hex | 30d8af3e7 |
13112112103 has 2 divisors, whose sum is σ = 13112112104. Its totient is φ = 13112112102.
The previous prime is 13112112071. The next prime is 13112112127. The reversal of 13112112103 is 30121121131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112112103 - 25 = 13112112071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112110103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556056051 + 6556056052.
It is an arithmetic number, because the mean of its divisors is an integer number (6556056052).
Almost surely, 213112112103 is an apocalyptic number.
13112112103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112112103 is an equidigital number, since it uses as much as digits as its factorization.
13112112103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 13112112103 its reverse (30121121131), we get a palindrome (43233233234).
The spelling of 13112112103 in words is "thirteen billion, one hundred twelve million, one hundred twelve thousand, one hundred three".
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