Base | Representation |
---|---|
bin | 111101000011101101… |
… | …1101110111001011111 |
3 | 110112110001200202202002 |
4 | 1322013123232321133 |
5 | 4122014012304043 |
6 | 140123010352515 |
7 | 12321206630663 |
oct | 1720733567137 |
9 | 415401622662 |
10 | 131121213023 |
11 | 50676563069 |
12 | 214b428b73b |
13 | c498271aa8 |
14 | 64bc36a8a3 |
15 | 36264d9bb8 |
hex | 1e876eee5f |
131121213023 has 2 divisors, whose sum is σ = 131121213024. Its totient is φ = 131121213022.
The previous prime is 131121213007. The next prime is 131121213037. The reversal of 131121213023 is 320312121131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131121213023 - 24 = 131121213007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131121212986 and 131121213004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131121213623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560606511 + 65560606512.
It is an arithmetic number, because the mean of its divisors is an integer number (65560606512).
Almost surely, 2131121213023 is an apocalyptic number.
131121213023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121213023 is an equidigital number, since it uses as much as digits as its factorization.
131121213023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131121213023 its reverse (320312121131), we get a palindrome (451433334154).
The spelling of 131121213023 in words is "one hundred thirty-one billion, one hundred twenty-one million, two hundred thirteen thousand, twenty-three".
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