Base | Representation |
---|---|
bin | 11101110100000100001010… |
… | …000011011100100110100111 |
3 | 122012021001210122010202002112 |
4 | 131310010022003130212213 |
5 | 114141242232131132320 |
6 | 1142512132002231235 |
7 | 36422124124136060 |
oct | 3564041203344647 |
9 | 565231718122075 |
10 | 131121225255335 |
11 | 38863221373757 |
12 | 1285820905551b |
13 | 58218a8832a33 |
14 | 2454430573567 |
15 | 1025b6d63dec5 |
hex | 77410a0dc9a7 |
131121225255335 has 32 divisors (see below), whose sum is σ = 183775820931072. Its totient is φ = 87938117435520.
The previous prime is 131121225255299. The next prime is 131121225255403. The reversal of 131121225255335 is 533552522121131.
It is not a de Polignac number, because 131121225255335 - 234 = 131104045386151 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131121225255292 and 131121225255301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25038911 + ... + 29819280.
It is an arithmetic number, because the mean of its divisors is an integer number (5742994404096).
Almost surely, 2131121225255335 is an apocalyptic number.
131121225255335 is a deficient number, since it is larger than the sum of its proper divisors (52654595675737).
131121225255335 is a wasteful number, since it uses less digits than its factorization.
131121225255335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54859703.
The product of its digits is 270000, while the sum is 41.
Adding to 131121225255335 its reverse (533552522121131), we get a palindrome (664673747376466).
The spelling of 131121225255335 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred twenty-five million, two hundred fifty-five thousand, three hundred thirty-five".
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