Base | Representation |
---|---|
bin | 10011000101001010011… |
… | …001000110111100010100 |
3 | 11122100110200211000221001 |
4 | 103011022121012330110 |
5 | 132440331024340200 |
6 | 2442210223433044 |
7 | 163506040431205 |
oct | 23051231067424 |
9 | 4570420730831 |
10 | 1311213121300 |
11 | 46609a695195 |
12 | 192156755784 |
13 | 96854221564 |
14 | 4766a8955ac |
15 | 2419356176a |
hex | 1314a646f14 |
1311213121300 has 72 divisors (see below), whose sum is σ = 2881098332280. Its totient is φ = 517908019200.
The previous prime is 1311213121261. The next prime is 1311213121301. The reversal of 1311213121300 is 31213121131.
It can be written as a sum of positive squares in 12 ways, for example, as 952443268624 + 358769852676 = 975932^2 + 598974^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311213121301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6676102 + ... + 6869698.
It is an arithmetic number, because the mean of its divisors is an integer number (40015254615).
Almost surely, 21311213121300 is an apocalyptic number.
1311213121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311213121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1440549166140).
1311213121300 is an abundant number, since it is smaller than the sum of its proper divisors (1569885210980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311213121300 is a wasteful number, since it uses less digits than its factorization.
1311213121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 194461 (or 194454 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1311213121300 its reverse (31213121131), we get a palindrome (1342426242431).
The spelling of 1311213121300 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, one hundred twenty-one thousand, three hundred".
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