Base | Representation |
---|---|
bin | 10011000101001010011… |
… | …001000111001000000101 |
3 | 11122100110200211001221221 |
4 | 103011022121013020011 |
5 | 132440331024401203 |
6 | 2442210223440341 |
7 | 163506040433332 |
oct | 23051231071005 |
9 | 4570420731857 |
10 | 1311213122053 |
11 | 46609a69580a |
12 | 1921567560b1 |
13 | 968542219c3 |
14 | 4766a895989 |
15 | 24193561abd |
hex | 1314a647205 |
1311213122053 has 2 divisors, whose sum is σ = 1311213122054. Its totient is φ = 1311213122052.
The previous prime is 1311213122003. The next prime is 1311213122077. The reversal of 1311213122053 is 3502213121131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 770248459044 + 540964663009 = 877638^2 + 735503^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311213122053 - 221 = 1311211024901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311213122003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606561026 + 655606561027.
It is an arithmetic number, because the mean of its divisors is an integer number (655606561027).
Almost surely, 21311213122053 is an apocalyptic number.
It is an amenable number.
1311213122053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311213122053 is an equidigital number, since it uses as much as digits as its factorization.
1311213122053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1311213122053 its reverse (3502213121131), we get a palindrome (4813426243184).
The spelling of 1311213122053 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, one hundred twenty-two thousand, fifty-three".
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