Base | Representation |
---|---|
bin | 111101000011101110… |
… | …0100100111010111111 |
3 | 110112110002010000021122 |
4 | 1322013130210322333 |
5 | 4122014041344203 |
6 | 140123015221155 |
7 | 12321211542056 |
oct | 1720734447277 |
9 | 415402100248 |
10 | 131121434303 |
11 | 506766a4342 |
12 | 214b43777bb |
13 | c49831b722 |
14 | 64bc3c739d |
15 | 3626530538 |
hex | 1e87724ebf |
131121434303 has 2 divisors, whose sum is σ = 131121434304. Its totient is φ = 131121434302.
The previous prime is 131121434291. The next prime is 131121434329. The reversal of 131121434303 is 303434121131.
It is an a-pointer prime, because the next prime (131121434329) can be obtained adding 131121434303 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131121434303 - 24 = 131121434287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131121434363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560717151 + 65560717152.
It is an arithmetic number, because the mean of its divisors is an integer number (65560717152).
Almost surely, 2131121434303 is an apocalyptic number.
131121434303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121434303 is an equidigital number, since it uses as much as digits as its factorization.
131121434303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 131121434303 its reverse (303434121131), we get a palindrome (434555555434).
The spelling of 131121434303 in words is "one hundred thirty-one billion, one hundred twenty-one million, four hundred thirty-four thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •