Base | Representation |
---|---|
bin | 11000011011000110… |
… | …00111011100010111 |
3 | 1020211210221100022201 |
4 | 30031203013130113 |
5 | 203323211224343 |
6 | 10005040105331 |
7 | 642634646026 |
oct | 141543073427 |
9 | 36753840281 |
10 | 13112211223 |
11 | 5619557401 |
12 | 265b305247 |
13 | 130c6cc687 |
14 | 8c56188bd |
15 | 51b21994d |
hex | 30d8c7717 |
13112211223 has 2 divisors, whose sum is σ = 13112211224. Its totient is φ = 13112211222.
The previous prime is 13112211193. The next prime is 13112211241. The reversal of 13112211223 is 32211221131.
It is a strong prime.
It is an emirp because it is prime and its reverse (32211221131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13112211223 - 217 = 13112080151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13112211223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112215223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556105611 + 6556105612.
It is an arithmetic number, because the mean of its divisors is an integer number (6556105612).
Almost surely, 213112211223 is an apocalyptic number.
13112211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112211223 is an equidigital number, since it uses as much as digits as its factorization.
13112211223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 19.
Adding to 13112211223 its reverse (32211221131), we get a palindrome (45323432354).
The spelling of 13112211223 in words is "thirteen billion, one hundred twelve million, two hundred eleven thousand, two hundred twenty-three".
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