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13112211241 is a prime number
BaseRepresentation
bin11000011011000110…
…00111011100101001
31020211210221100100101
430031203013130221
5203323211224431
610005040105401
7642634646053
oct141543073451
936753840311
1013112211241
115619557418
12265b305261
13130c6cc69c
148c56188d3
1551b219961
hex30d8c7729

13112211241 has 2 divisors, whose sum is σ = 13112211242. Its totient is φ = 13112211240.

The previous prime is 13112211223. The next prime is 13112211251. The reversal of 13112211241 is 14211221131.

13112211241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12593328400 + 518882841 = 112220^2 + 22779^2 .

It is an emirp because it is prime and its reverse (14211221131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112211241 - 211 = 13112209193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13112211251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556105620 + 6556105621.

It is an arithmetic number, because the mean of its divisors is an integer number (6556105621).

Almost surely, 213112211241 is an apocalyptic number.

It is an amenable number.

13112211241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112211241 is an equidigital number, since it uses as much as digits as its factorization.

13112211241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96, while the sum is 19.

Adding to 13112211241 its reverse (14211221131), we get a palindrome (27323432372).

The spelling of 13112211241 in words is "thirteen billion, one hundred twelve million, two hundred eleven thousand, two hundred forty-one".