Base | Representation |
---|---|
bin | 10011000101001010111… |
… | …011110110110100110011 |
3 | 11122100111022221211011021 |
4 | 103011022323312310303 |
5 | 132440340342332243 |
6 | 2442211151000311 |
7 | 163506211030135 |
oct | 23051273666463 |
9 | 4570438854137 |
10 | 1311222230323 |
11 | 4660a4846a05 |
12 | 192159809097 |
13 | 96856090705 |
14 | 4766bb87055 |
15 | 241942606ed |
hex | 1314aef6d33 |
1311222230323 has 2 divisors, whose sum is σ = 1311222230324. Its totient is φ = 1311222230322.
The previous prime is 1311222230321. The next prime is 1311222230359. The reversal of 1311222230323 is 3230322221131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311222230323 - 21 = 1311222230321 is a prime.
Together with 1311222230321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1311222230321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655611115161 + 655611115162.
It is an arithmetic number, because the mean of its divisors is an integer number (655611115162).
Almost surely, 21311222230323 is an apocalyptic number.
1311222230323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311222230323 is an equidigital number, since it uses as much as digits as its factorization.
1311222230323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1311222230323 its reverse (3230322221131), we get a palindrome (4541544451454).
The spelling of 1311222230323 in words is "one trillion, three hundred eleven billion, two hundred twenty-two million, two hundred thirty thousand, three hundred twenty-three".
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